DOC: CoW and chained assignments: add solution #63310
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| need to convert the column name to its position using :meth:`Index.get_loc` or you need | ||
| to convert the row position to its index. Both variants as shown in the following snippet: | ||
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| .. code-block:: ipython |
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We only use code-block when demonstrating old behavior that is no longer the case. Can you instead use .. ipython:: python (see other sections of this file for examples).
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Sure, will do!
This distinction just wasn't obvious at all - it just seemed random to me.
| need to convert the column name to its position using :meth:`Index.get_loc` or you need | ||
| to convert the row position to its index. Both variants as shown in the following snippet: | ||
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| .. ipython:: python |
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I would maybe move this example to the "Chained Assignment" section below (and we can link from here to there, indicating that writing it as a single statement has to avoid chained assignment).
Because in the end, the question here is how to write df["foo"].iloc[0] = 100 without chained assignment. I think it is good to show that as an explicit example, since I think this is a quite common use case currently of chained assignment (as it is the only way to combine positional/label based without using the workarounds shown here).
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doc/source/whatsnew/vX.X.X.rstfile if fixing a bug or adding a new feature.AGENTS.md.